Vladmodels Zhenya -y114- Sets 1 70.251 ((better)) › ❲CERTIFIED❳

Problem Statement: Given a set of intervals on the real line, find the minimum number of sets required to cover all the intervals. Problem Details:

The input consists of a set of intervals, where each interval is a pair of real numbers representing the start and end points of the interval. The goal is to find the minimum number of sets required to cover all the intervals.

Approach:

Sort the Intervals: Sort the intervals based on their end points. This is because we want to cover the intervals that end earliest first. Initialize the Result: Initialize the result with the first interval. Iterate through the Intervals: Iterate through the remaining intervals. For each interval, check if it overlaps with the last interval in the result. If it does not overlap, add it to the result. Vladmodels Zhenya -y114- Sets 1 70.251

Code Solution: def min_sets(intervals): if not intervals: return 0

# Sort the intervals based on their end points intervals.sort(key=lambda x: x[1])

# Initialize the result with the first interval result = [intervals[0]] Problem Statement: Given a set of intervals on

# Iterate through the remaining intervals for current_interval in intervals[1:]: # Get the last interval in the result last_interval = result[-1]

# Check if the current interval overlaps with the last interval if current_interval[0] > last_interval[1]: # If it does not overlap, add it to the result result.append(current_interval)

# Return the minimum number of sets required return len(result) Approach: Sort the Intervals: Sort the intervals based

# Example usage intervals = [[1, 3], [2, 4], [5, 7], [6, 8]] print(min_sets(intervals)) # Output: 2

Explanation: